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rumus matematik

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Post time 16-1-2009 01:01 PM | Show all posts |Read mode
bagaimana untuk buktikan rumus untuk kecerunan iaitu y1/ x1 ??

bagaimana pula dgn rumus utk laju??
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Post time 16-1-2009 01:04 PM | Show all posts
s=d/t ....laju

[ Last edited by  emiliahani at 16-1-2009 01:12 PM ]
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Post time 16-1-2009 01:06 PM | Show all posts
dari rumus y=mx+c...........
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Post time 16-1-2009 01:06 PM | Show all posts
kecerunan iaitu y1/ x1 ??



tak paham yang nih
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Post time 16-1-2009 01:08 PM | Show all posts
kecerunan yang graf die camne.......linear ke kuadratik ker
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Post time 16-1-2009 01:11 PM | Show all posts
ohhh...nk derive yang rumus laju yang ade 5 rumus tuh ker
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Post time 16-1-2009 02:39 PM | Show all posts
kena buka semula le teks form 4 & 5 tu...
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Post time 16-1-2009 04:50 PM | Show all posts
G:\bebas\PhysicsLAB Derivation of the Kinematics Equations for Uniformly Accelerated Motion.htm
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Post time 19-1-2009 09:52 PM | Show all posts
m = TAN ϑ
TAN ϑ = (y2 - y1)/(x2-x1)

v = dS/dt
a = dv/dt

S = y
t = x
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Post time 22-1-2009 10:03 PM | Show all posts

Reply #1 jueaz's post

ni cam aljabar niskala je.....
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Post time 23-1-2009 11:03 AM | Show all posts
sudah lupa,...ada yg boleh tunjukkan ke

[ Last edited by  silver_nano59 at 23-1-2009 11:05 AM ]
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Post time 23-1-2009 12:10 PM | Show all posts
bukan ke e=mc kuasa 2?

hehe lupa la



salam newbie
----------------

http://che-mie.blogspot.com
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Post time 4-2-2009 01:41 PM | Show all posts
Instead of derive, aku rse itu (rumus kecerunan) lebih kpde definition....

Laju pun sme gak, ikut definition. Iaitu first derivative of distance. Dr situ dtg ds/dt.


Both questions, berbalik kpde definition...


Bnde ni sme gak dgn 'cmne newton derive rumus F=ma'. Newton x derive rumus tu, newton cume define force...
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