Help : Macam mana nak kira Umur dari DOB using PHP

alisetan

Salam guys,
sory baru nak menapak dalam php.

Ali tgh develope satu sistem yang memerlukan pengiraan umur. Igatkan masalah dah solve bila ali jupe satu kding tuh, mmg dia leh kira umur. tp kira umur dr tahun lahir jer. So sekarang nih bos ali nak suruh ali cari plak pengiraan yang exactly boleh kira hari dan bulan lahir. Cth : katalah ali lahir 1/12/1980..
kalau kira by tahun umur ALi hari ni (2/11/2009)ialah  29 tahun,
tapi bos ali x nak mcm tuh dia nak umur tuh tepat cam umur Alli hari ini ialah 28 tahun 11 bulan 1 hari.

anyone, help me. thanks

BorderManager

1. <?
   
2. function date_diff($d1, $d2)
   
3. {
   
4.   if ($d1 < $d2){
   
5.     $temp = $d2;
   
6.     $d2 = $d1;
   
7.     $d1 = $temp;
   
8.   }else{
   
9.     $temp = $d1;
   
10.   }
    
11.   $d1 = date_parse(date("Y-m-d H:i:s",$d1));
    
12.   $d2 = date_parse(date("Y-m-d H:i:s",$d2));
    
13.   //seconds
    
14.   if ($d1['second'] >= $d2['second']){
    
15.     $diff['second'] = $d1['second'] - $d2['second'];
    
16.   }
    
17.   else {
    
18.     $d1['minute']--;
    
19.     $diff['second'] = 60-$d2['second']+$d1['second'];
    
20.   }
    
21.   //minutes
    
22.   if ($d1['minute'] >= $d2['minute']){
    
23.     $diff['minute'] = $d1['minute'] - $d2['minute'];
    
24.   }
    
25.   else {
    
26.     $d1['hour']--;
    
27.     $diff['minute'] = 60-$d2['minute']+$d1['minute'];
    
28.   }
    
29.   //hours
    
30.   if ($d1['hour'] >= $d2['hour']){
    
31.     $diff['hour'] = $d1['hour'] - $d2['hour'];
    
32.   }
    
33.   else {
    
34.     $d1['day']--;
    
35.     $diff['hour'] = 24-$d2['hour']+$d1['hour'];
    
36.   }
    
37.   //days
    
38.   if ($d1['day'] >= $d2['day']){
    
39.     $diff['day'] = $d1['day'] - $d2['day'];
    
40.   }
    
41.   else {
    
42.     $d1['month']--;
    
43.     $diff['day'] = date("t",$temp)-$d2['day']+$d1['day'];
    
44.   }
    
45.   //months
    
46.   if ($d1['month'] >= $d2['month']){
    
47.     $diff['month'] = $d1['month'] - $d2['month'];
    
48.   }
    
49.   else {
    
50.     $d1['year']--;
    
51.     $diff['month'] = 12-$d2['month']+$d1['month'];
    
52.   }
    
53.   //years
    
54.   $diff['year'] = $d1['year'] - $d2['year'];
    
55.   return $diff;   
    
56. }
    
57. 
    
58. $born_date = mktime(6,30,1,4,15,1977);
    
59. $date_diff_array = date_diff($born_date, time());
    
60. echo 'Age = '. $date_diff_array['year'] .' y '. $date_diff_array['month'].' m '. $date_diff_array['day'] .' d';
    
61. ?>

Copy the Code

ana_una

$born_date = mktime(6,30,1,4,15,1977); <----- befday tuan manager ke ni?Glemer tauuu...

ok... ni modified code yg bole tambah utk baca variable utk tarikh lahir..
sori erkk tuan manager.. haijek skrip skit... kalo salah tolong betoikan...

1. 
   
2. <?
   
3. function date_diff($d1, $d2)
   
4. {
   
5.   if ($d1 < $d2){
   
6.     $temp = $d2;
   
7.     $d2 = $d1;
   
8.     $d1 = $temp;
   
9.   }else{
   
10.     $temp = $d1;
    
11.   }
    
12.   $d1 = date_parse(date("Y-m-d H:i:s",$d1));
    
13.   $d2 = date_parse(date("Y-m-d H:i:s",$d2));
    
14.   //seconds
    
15.   if ($d1['second'] >= $d2['second']){
    
16.     $diff['second'] = $d1['second'] - $d2['second'];
    
17.   }
    
18.   else {
    
19.     $d1['minute']--;
    
20.     $diff['second'] = 60-$d2['second']+$d1['second'];
    
21.   }
    
22.   //minutes
    
23.   if ($d1['minute'] >= $d2['minute']){
    
24.     $diff['minute'] = $d1['minute'] - $d2['minute'];
    
25.   }
    
26.   else {
    
27.     $d1['hour']--;
    
28.     $diff['minute'] = 60-$d2['minute']+$d1['minute'];
    
29.   }
    
30.   //hours
    
31.   if ($d1['hour'] >= $d2['hour']){
    
32.     $diff['hour'] = $d1['hour'] - $d2['hour'];
    
33.   }
    
34.   else {
    
35.     $d1['day']--;
    
36.     $diff['hour'] = 24-$d2['hour']+$d1['hour'];
    
37.   }
    
38.   //days
    
39.   if ($d1['day'] >= $d2['day']){
    
40.     $diff['day'] = $d1['day'] - $d2['day'];
    
41.   }
    
42.   else {
    
43.     $d1['month']--;
    
44.     $diff['day'] = date("t",$temp)-$d2['day']+$d1['day'];
    
45.   }
    
46.   //months
    
47.   if ($d1['month'] >= $d2['month']){
    
48.     $diff['month'] = $d1['month'] - $d2['month'];
    
49.   }
    
50.   else {
    
51.     $d1['year']--;
    
52.     $diff['month'] = 12-$d2['month']+$d1['month'];
    
53.   }
    
54.   //years
    
55.   $diff['year'] = $d1['year'] - $d2['year'];
    
56.   return $diff;   
    
57. }
    
58. ////////////////////// edit disini //////////////////////////////////////////
    
59. $born_date="1977-04-15"; // call variable tarikh lahir tukar ke ---> $born_date=$row['born_date'];
    
60. $born_date=explode ("-",$born_date); //pecah2kan tarikh lahir tu
    
61. $born_date = mktime(6,30,1,$born_date[1],$born_date[2],$born_date[0]);
    
62. ////////////////////// tamat edit disini ///////////////////////////////////
    
63. 
    
64. //$born_date = mktime(6,30,1,4,15,1977);
    
65. $date_diff_array = date_diff($born_date, time());
    
66. echo 'Age = '. $date_diff_array['year'] .' y '. $date_diff_array['month'].' m '. $date_diff_array['day'] .' d';
    
67. ?>

Copy the Code

ana_una

apasal dah tukar kaler tamo kuar kaler???

BorderManager

peh.. bijok akak n... hehe tu bday sapa tah....

alisetan

terima kasih banyak2 atas pertolongan.
dah berjaya.

ana_una

5# BorderManager

toche..toche...
tu pasal lama kene benam..
peram lama2...

ana_una

terima kasih banyak2 atas pertolongan.
dah berjaya.

alisetan Post at 2-11-2009 16:38

sama-sama banyak2...

alisetan

mintak tulun sekali lagi boleh?

date saya format dia d-m-y, so bila sy convert ker y-m-d dia jadi tapi dia x leh calculate..kenapa yer

ni koding yg sy pakai tok convert

$born_date="02/03/1979"; // call variable tarikh lahir tukar ke ---> $born_date=$row['born_date'];
echo 'Tarikh lahir =' .$born_date;
echo "<br>";
$born_date=explode ("/",$born_date);
krsort($born_date);        print "<p>".implode("/",$born_date)."</p>";  tu

$born_date = mktime(6,30,1,$born_date[1],$born_date[2],$born_date[0]);
echo $born_date;

BorderManager

ko terbalik tu...

$born_date = mktime(6,30,1,$born_date[1],$born_date[0],$born_date[2]);

mktime ($hour, $minute, $second, $month, $day, $year);

alisetan

thank u bro

dune1989

wah, ada pakar PHP la..
nak copy nih he4..

BorderManager

copy je.. FOC

ana_una

copy je.. FOC
BorderManager Post at 8-11-2009 23:50

kalo camtu nk claim pd tuan manager le...

isms

edited....

isms

Reply 13# BorderManager


    macam mana pulak kalau kita nak kira date_diff antara dua tarikh.
cth kalau saya ada date1=13/4/1999 dan date2=01/03/2011,
sy cuba modified coding BM bagi tp x jadilah, output asik 41y, 2m, 0 d
sy wt cam ne
------------------------------------------------------------
$date_diff;
$born_date=$date2;
$born_date=explode ("/",$born_date);
krsort($born_date);        
implode("/",$born_date);
$born_date = mktime(6,30,1,$born_date[1],$born_date[0],$born_date[2]);
                        
                                                
$date_diff_array = date_diff($date1, $born_date);
$beza = $date_diff_array['year'] .' y '. $date_diff_array['month'].' m '. $date_diff_array['day'] .' d';

--------------------------------
boleh tolong bgtau tak tang mana yg salah...

BorderManager

1. <?php
   
2. function date_diff($d1, $d2)
   
3. {
   
4.   if ($d1 < $d2){
   
5.     $temp = $d2;
   
6.     $d2 = $d1;
   
7.     $d1 = $temp;
   
8.   }else{
   
9.     $temp = $d1;
   
10.   }
    
11.   $d1 = date_parse(date("Y-m-d H:i:s",$d1));
    
12.   $d2 = date_parse(date("Y-m-d H:i:s",$d2));
    
13.   //seconds
    
14.   if ($d1['second'] >= $d2['second']){
    
15.     $diff['second'] = $d1['second'] - $d2['second'];
    
16.   }
    
17.   else {
    
18.     $d1['minute']--;
    
19.     $diff['second'] = 60-$d2['second']+$d1['second'];
    
20.   }
    
21.   //minutes
    
22.   if ($d1['minute'] >= $d2['minute']){
    
23.     $diff['minute'] = $d1['minute'] - $d2['minute'];
    
24.   }
    
25.   else {
    
26.     $d1['hour']--;
    
27.     $diff['minute'] = 60-$d2['minute']+$d1['minute'];
    
28.   }
    
29.   //hours
    
30.   if ($d1['hour'] >= $d2['hour']){
    
31.     $diff['hour'] = $d1['hour'] - $d2['hour'];
    
32.   }
    
33.   else {
    
34.     $d1['day']--;
    
35.     $diff['hour'] = 24-$d2['hour']+$d1['hour'];
    
36.   }
    
37.   //days
    
38.   if ($d1['day'] >= $d2['day']){
    
39.     $diff['day'] = $d1['day'] - $d2['day'];
    
40.   }
    
41.   else {
    
42.     $d1['month']--;
    
43.     $diff['day'] = date("t",$temp)-$d2['day']+$d1['day'];
    
44.   }
    
45.   //months
    
46.   if ($d1['month'] >= $d2['month']){
    
47.     $diff['month'] = $d1['month'] - $d2['month'];
    
48.   }
    
49.   else {
    
50.     $d1['year']--;
    
51.     $diff['month'] = 12-$d2['month']+$d1['month'];
    
52.   }
    
53.   //years
    
54.   $diff['year'] = $d1['year'] - $d2['year'];
    
55.   return $diff;   
    
56. }
    
57. 
    
58. $date1 = '13/4/1999';
    
59. $date1 = explode ("/",$date1);
    
60. $date1 = mktime(0, 0, 0, $date1[1], $date1[0], $date1[2]);
    
61. 
    
62. $date2 = '01/03/2011';
    
63. $date2=explode ("/",$date2);
    
64. $date2 = mktime(0, 0, 0, $date2[1], $date2[0], $date2[2]);
    
65. 
    
66. $date_diff_array = date_diff($date1, $date2);
    
67. echo 'Date diff = '. $date_diff_array['year'] .' y '. $date_diff_array['month'].' m '. $date_diff_array['day'] .' d';
    
68. 
    
69. ?>

Copy the Code

isms

Reply 17# BorderManager

terima kasih banyak2 bro.

isms

BorderManager replied at 22-3-2011 10:32 AM

Bro BorderManager,

sy ada koding spt kat bawah ne.
sy dh buat if else statement utk beza kan kaler font untuk value yg berbeza2
cthnya, kalau value tuh lebih >=0 dan <=14, font tukar kaler hijo
kalau  selain tuh kaler merah.

sy rs if else stament tuh dh betui dh
cumanya, dia mcm x boleh bc value tuh
menyebablan semua kaler hijo shj wpun ada yg lebih dr 14 hari.

lepas tuh mcm mana yer sy nk convert tahun dh bulan ke bilangan hari shj
cth 1y 2m 10 day(ne cth output), sbb ne kot dia x recognize value, menyebabkan semua jadi kaler hijo.
cth tuh sy nak convert ke integer shj, tok menjadikan ker 435 hari. contohnya lah.

            $accComplDt    = trim($row['ACC_COMPL_DT']);
            $date1 = $accComplDt;//'01/09/2015';
            $date1 = explode ("/",$date1);
            $date1 = mktime(0, 0, 0, $date1[1], $date1[0], $date1[2]);
            
            $accDate    = trim($row['ACC_DATE']);
            $date2 = $accDate;//'02/10/2015';
            $date2=explode ("/",$date2);
            $date2 = mktime(0, 0, 0, $date2[1], $date2[0], $date2[2]);
            $date_diff_array = date_diff($date1, $date2);
                        
            $Tempoh = $date_diff_array['year'] .' y '. $date_diff_array['month'].' m '. $date_diff_array['day'] .' d';
            //$Tempoh = $date_diff_array['day'] .' d';
            
            if (($Tempoh >= 0) ||(Tempoh <=14))
                     {
                           echo "<font color=\"#006600\">" .$Tempoh;
                        
                      } else {
                            echo "<font color=\"#FF0000\">" .$Tempoh;
                        
                             }

BorderManager

isms replied at 7-10-2015 03:36 PM
Bro BorderManager,

sy ada koding spt kat bawah ne.

query dlm SQL terus je

"SELECT IF(DATEDIFF(ACC_COMPL_DT, ACC_COMPL_DT) AS day FROM table";


print '<span style="color: '. ($row['day'] >= 0 || $row['day'] <= 14 ? '#006600' : '#FF0000') .'">'. $row['day'] .'</span>';