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Samsul menaiki motosikal ke kedai dengan kelajuan 20km/j.
Semasa pulang dia bergegas dengan memandu pada purata kelajuan 30 km/j. Berapakah purata kelajuan pergi dan balik?? 
Last edited by xpdckelate on 12-3-2013 05:51 PM
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takde jarak diberikan so..............................................
ermmmmm 20km/j....................................................
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Elle_mujigae posted on 12-3-2013 05:54 PM 
takde jarak diberikan so..............................................
ermmmmm 20km/j............ ...
nope,he2...ni soklan math,ada formula dia,ahaks 
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24km/j...... |
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Total average speed = Total distance / Total time
Speed,S = Distance,D /Time,t
substitute t= D/ S into the formula...
Simplest formula jadi;
Total average speed = 2S1*S2/ (S1+s2)
Last edited by Elle_mujigae on 12-3-2013 06:19 PM
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i miss my lovely physics teacher.... |
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25 km/j |
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Elle_mujigae posted on 12-3-2013 06:03 PM
24km/j......
TAHNIAH,he2
nah adiah
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anna-zara posted on 12-3-2013 08:12 PM
25 km/j
nope...jawapan dia 24km/j
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Elle_mujigae posted on 12-3-2013 06:18 PM
Total average speed = Total distance / Total time
Speed,S = Distance,D /Time,t
formula dia camni
J : Jarak
M1 : Masa pergi kedai
M2 : Masa balik dari kedai
P : Purata kelajuan
J = 20 * M1
M1 = J/20
J = 30 * M2
M2= J/30
2J = P(M1 + M2)
2J = P(J/20 + J/30)
2J = P(3J/60 + 2J/60)
2J = P(5J/60)
P= 120J/5J
P= 24 km/j
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oooooooooooo...aku men hentam je td |
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anna-zara posted on 12-3-2013 10:59 PM
oooooooooooo...aku men hentam je td
jawapan biasa adalah 25km/j sebab diorang kira camni (20km/j + 30km/j) / 2,he2
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xpdckelate posted on 12-3-2013 10:39 PM
TAHNIAH,he2
nah adiah
Motor apa ni.....
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Post time 12-3-2013 05:49 PM
变色卡
Post time 12-3-2013 05:54 PM
Author
